2x/x^2-16=8/x^2-16-2/x+4

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Solution for 2x/x^2-16=8/x^2-16-2/x+4 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

(2*x)/(x^2)-16 = 8/(x^2)-(2/x)-16+4 // - 8/(x^2)-(2/x)-16+4

(2*x)/(x^2)+2/x-(8/(x^2))-16-4+16 = 0

(2*x)/(x^2)+2/x-8*x^-2-16-4+16 = 0

4*x^-1-8*x^-2-4 = 0

t_1 = x^-1

4*t_1^1-8*t_1^2-4 = 0

4*t_1-8*t_1^2-4 = 0

DELTA = 4^2-(-8*(-4)*4)

DELTA = -112

DELTA < 0

x belongs to the empty set

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